Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
Solution:
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public TreeNode sortedArrayToBST(int[] nums) {
return sortedArrayToBST(nums, 0, nums.length-1);
}
public TreeNode sortedArrayToBST(int[] nums, int l, int r) {
if(l>r) return null;
int mid = l + (r - l) / 2;
TreeNode root = new TreeNode(nums[mid]);
root.left = sortedArrayToBST(nums, l, mid-1);
root.right = sortedArrayToBST(nums, mid+1, r);
return root;
}
}