Find Minimum in Rotated Sorted Array II

Follow up for “Find Minimum in Rotated Sorted Array”: What if duplicates are allowed?

Would this affect the run-time complexity? How and why?
Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

Find the minimum element.

The array may contain duplicates.

Solution:

public class Solution {
    public int findMin(int[] nums) {
        int lo=0, hi=nums.length-1;
        while(lo<hi){
            int mid = (lo+hi)/2;
            while(mid<hi && nums[mid]==nums[hi]) hi--;
            while(mid>lo && nums[mid]==nums[lo]) lo++;
            if(nums[mid]>nums[hi]) lo = mid+1;
            else hi=mid;
        }
        return nums[lo];
    }
}
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