Queue Recontruction by Height

Suppose you have a random list of people standing in a queue. Each person is described by a pair of integers (h, k), where h is the height of the person and k is the number of people in front of this person who have a height greater than or equal to h. Write an algorithm to reconstruct the queue.

Note: The number of people is less than 1,100.

Example

Input:
[[7,0], [4,4], [7,1], [5,0], [6,1], [5,2]]

Output:
[[5,0], [7,0], [5,2], [6,1], [4,4], [7,1]]

Solution:

public class Solution {
    public int[][] reconstructQueue(int[][] people) {
        Arrays.sort(people, (a,b)->(a[0]==b[0] ? a[1]-b[1] : b[0]-a[0]));
        List<int[]> list = new LinkedList<>();
        for(int[] p : people) list.add(p[1], p);
        return list.toArray(new int[people.length][]);
    }
}
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