Two elements of a binary search tree (BST) are swapped by mistake.
Recover the tree without changing its structure.
Note: A solution using O(n) space is pretty straight forward. Could you devise a constant space solution?
Solution:
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public void recoverTree(TreeNode root) {
TreeNode pre=null, first=null, second=null;
Stack<TreeNode> stack = new Stack<>();
while(root!=null || !stack.isEmpty()){
while(root!=null){
stack.push(root);
root = root.left;
}
root = stack.pop();
if(pre!=null && pre.val>root.val){
if(first==null){
first = pre;
second = root;
} else {
second = root;
}
}
pre = root;
root = root.right;
}
int tmp = first.val;
first.val = second.val;
second.val = tmp;
}
}