Unique Binary Search Trees II

Given an integer n, generate all structurally unique BST’s (binary search trees) that store values 1…n.

For example, Given n = 3, your program should return all 5 unique BST’s shown below.

   1         3     3      2      1
    \       /     /      / \      \
     3     2     1      1   3      2
    /     /       \                 \
   2     1         2                 3

Solution:

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public List<TreeNode> generateTrees(int n) {
        if(n<1) return new ArrayList<>();
        return generateTrees(1,n);
    }
    public List<TreeNode> generateTrees(int start, int end) {
        List<TreeNode> ans = new ArrayList<>();
        if(start>end){
            ans.add(null);
            return ans;
        }
        for(int i=start; i<=end; i++){
            List<TreeNode> left = generateTrees(start,i-1);
            List<TreeNode> right = generateTrees(i+1,end);
            for(TreeNode l : left){
                for(TreeNode r : right){
                    TreeNode root = new TreeNode(i);
                    root.left = l;
                    root.right = r;
                    ans.add(root);
                }
            }
        }
        return ans;
    }
}
comments powered by Disqus