Follow up for “Unique Paths”:
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1 and 0 respectively in the grid.
For example, There is one obstacle in the middle of a 3x3 grid as illustrated below.
[
[0,0,0],
[0,1,0],
[0,0,0]
]
Solution:
public class Solution {
public int uniquePathsWithObstacles(int[][] obstacleGrid) {
int[][] dp = new int[obstacleGrid.length+1][obstacleGrid[0].length+1];
dp[1][0] = 1;
for(int i=1; i<=obstacleGrid.length; i++){
for(int j=1; j<=obstacleGrid[0].length; j++){
if(obstacleGrid[i-1][j-1]==1) dp[i][j] = 0;
else dp[i][j] = dp[i-1][j] + dp[i][j-1];
}
}
return dp[obstacleGrid.length][obstacleGrid[0].length];
}
}